Question 1028857
Find the slope of this line										                                                                                                            	
											
1	y  	=	  1/ 6	x	+	3    					
Divide by	1										
	y  	=	  1/ 6	x	+	3    					
Compare this equation with y=mx+b,					m= slope & b= y intercept						
slope m =	 1/6										
											
The slope of a line perpendicular to the above line will be the negative reciprocal										-6    	
Because m1*m2 =-1											
The slope of the required line will be			-6    								
											
m=	-6    	,point	(	-3	,	23	)				
Find b by plugging the values of m & the point in											
y=mx+b											
23	=	18      	+	b							
b=	5    										
m=	-6    										
The required equation is		y  	=	-6      	x	+	5      				
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