Question 1028749
You don't provide enough information to solve.
You need 5 roots.
You provided 4 roots (complex conjugate is also a root since coefficients are real).
You could have multiplicity of 2 for the real roots so there may be two possible solutions,
{{{f(x)=(x+1)^2(x-5)(x-(3+i))(x-(3-i))}}}
{{{f(x)=(x+1)^2(x-5)^2(x-(3+i))(x-(3-i))}}}
But I don't think that's the solution you're looking for.
Please repost with additional information.