Question 1028635
Part of a machine moves with a velocity given by the expression:7t^2+0.8tmm/s. 

Calculate the displacement over the first 5 seconds of motion.
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velocity is the 1st derivative of position, so integrate the expression
--> F(t) = 7t^3/3 + 0.4t^2 mm
F(5) = 7*125/3 + 0.4*25 = 875/3 + 10
F(5) = 905/3 mms
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No initial conditions were given, so the constant of integration was assumed to be zero.