Question 1028625
The diagonal of the first square (using Pythaorean theorem),
{{{S[1]^2+S[1]^2=D[1]^2}}}
{{{D[1]=sqrt(2)*S[1]}}}
{{{D[1]=sqrt(2)}}}
{{{S[2]=sqrt(2)}}}
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{{{D[2]=sqrt(2)*S[2]}}}
{{{D[2]=sqrt(2)*sqrt(2)}}}
{{{D[2]=2}}}