Question 88119
1) {{{6y^2}}}-2yz
Factor out the 2y
2y(3y-z)

2) {{{8g^2}}}j-{{{12h^3}}}j
  Factor out 4j
4j({{{2g^2}}}-{{{3h^3}}})

3){{{s^2}}}-s-6
(s-3)(s+2)

4){{{y^2}}}-4y-5
(y-5)(y-1)
Hope I didn't get to it to late.
:)