Question 1028569
{{{x^2-4x+5+k=0}}}
{{{(x^2-4x+4)+5+k=4}}}
{{{(x-2)^2=-1-k}}}
{{{(x-2)^2=-(1+k)}}}
{{{x-2=0 +- sqrt(-1-k)}}}
{{{x=2 +- sqrt(-1-k)}}}
So use the lower zero,
{{{2-sqrt(-1-k)>0}}}
{{{-sqrt(-1-k)>-2}}}
{{{sqrt(-1-k)<2}}}
{{{-1-k<4}}}
{{{-k<5}}}
{{{k>-5}}}