Question 1028560
The shortest distance(d) from a point to a line is
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d = | Ax + By + C | / square root(A^2 +B^2)
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note that the standard form for a line is Ax +By + C = 0
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we are given
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Q(3,2) and line x +2y -3 = 0
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therefore
:
d = | 1(3) + 2(2) -3 | / square root(1^2 + 2^2)
:
d = 4 / square root(5) = 1.788854382 approx 1.8
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