Question 1028504
E. None of the above.

One "hole" in the graph exists at x = 2.  The graph is a hyperbola with horizontal asymptote y = 8/5 and vertical asymptote x = -2.
The function can be reduced to {{{f(x) = (8x)/(5(x+2))}}}, where {{{x<>2}}}.

The discontinuity at x = -2 cannot be considered a "hole", because it is an essential/infinite discontinuity.
Thus, there is only one "hole" in the graph.