Question 88508
Call one missing number "n". Then the other missing number is "n-4".
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The product of those two numbers is n times the quantity n - 4, and that product is 96.
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In equation form this is:
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{{{n*(n-4) = 96}}}
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Multiply out the left side and you get:
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{{{n^2 - 4n = 96}}}
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Get this quadratic equation into standard form by subtracting 96 from both sides. When you
do this subtraction, the equation becomes:
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{{{n^2 - 4n - 96 = 0}}}
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The left side can be factored and when you do that the equation is:
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{{{(n - 12)*(n + 8) = 0}}}
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This equation will be true if either of the factors on the left side equals zero because zero
times anything is zero. So we can say that either
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{{{n - 12 = 0}}} 
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which after adding 12 to both sides becomes {{{n = 12}}}
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or else
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{{{n + 8 = 0}}}
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which after subtracting 8 from both sides becomes {{{n = -8}}}
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So there are two possible answers for n. Either n = 12 or n = -8.
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Let's check them out. If n is 12 then n minus 4 is 8. And 12 times 8 is 96.  Therefore,
n = 12 checks out.
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If n = -8, then n minus 4 is -8 - 4 = -12. And -8 times -12 equals +96 so it checks out too.
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Both answers check out. So, again, n is either +12 or -8.
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Hope this helps you to understand the problem.