Question 1028411
1) Find the sum of all of the 3-digit positive integers.
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The sum from 100 to 999 = 900 integers
Add 450 pairs:
100 + 999 = 1099
101 + 998 = 1099
etc.
450*1099 = 494550
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my answer:  (999(99+1))/(2) - (99(99+1))/(2)
            (999(1000))/(2) - (99(100))/(2)
            (999(500)) - (99(50))
            499500 - 4950 = 494550*****
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2)  Find the sum of every integer from 1 to 1000 that is not a perfect square.
my answer:  ((1000)(1000+1))/(2)
             (500)(1001)
             500500*****
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That's the sum of all integers.
You have to subtract all the perfect squares.
1,4,9,16, etc up to 961