Question 1028399
Notice the progression for the 1st, 3rd and 5th elements
101 192 and 283
192 is 91 more than 101
283 is 91 more than 192
Now look at the 2nd, 4th elements
316 , 225
The difference for these two is 91,
so one could argue that the 6th element should
be 225 - 91 = 134
and the whole sequence would be
101,316,192,225,283,134