Question 1028331
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logx= log3+2log2-3/4log16
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<pre>
{{{log((x))}}} = {{{log((3)) + 2*log((2)) - (3/4)*log((16)))}}}  --->

{{{log((x))}}} = {{{log((3)) + 2*log((2)) - (3/4)*log((2^4)))}}}   --->   ( use {{{log((2^4))}}} = {{{4*log((2))}}} )   --->   

{{{log((x))}}} = {{{log((3)) + 2*log((2)) - (3/4)*4*log((2)))}}}   --->

{{{log((x))}}} = {{{log((3)) + 2*log((2)) - 3*log((2))}}}   --->

{{{log((x))}}} = {{{log((3)) - log((2))}}}   --->

{{{log((x))}}} = {{{log((3/2))}}} --->

x = {{{3/2}}}.
</pre>