Question 88498
Given that either 2 or -2 is a solution to each of the following, solve each equation 
x^3-2x^2-6x+12=0 


2/....1.... -2.... -6....+12
...............2......0.....-12
........1......0......-6..|..0

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Remainder is zero, so x=2 is a zero.
Quotient is x^2-6
Other zeroes are +sqrt6 and -sqrt6
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Cheers,
Stan H.