Question 88497
2. For the given equation 
log base y (x-1)+ log base y ( x^2+x+1)= 1 
A) solve for y. 

= log(base y) (x-1)(x^2+x+1) = 1

y = (x-1)(x^2+x+1)
y = x^3+x^2-x^2+x-x-1 = x^3-1
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B)Let y= f(x)and find f^-1 (x) 
y = x^3-1
Interchange x and y to get x = y^3-1
Sove for y as follows:
y^3=x+1
y = (x+1)^(1/3)
That is f^-1(x)
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Cheers,
Stan H.