Question 1028261
From
{{{x+1 = sqrt(19-x)}}}
we square both sides and get
{{{x^2 + 2x + 1 = 19 - x}}}
{{{x^2 + 3x - 18 = 0}}}
Now factor and solve...
(x + 6)(x - 3) = 0
x = -6  or x = 3
Now we plug in to see if any of these work out...
x = 3 works but x = -6 does not...so
x = 3