Question 1028107

Mark made a business trip of 181 miles.  He averaged 61 mph for the first part of the trip and 60 mph for the second part.  If the trip took 3 hours, how long did he travel at each rate?
First part:
Second part:
<pre>Let time he traveled at 61 mph, be T
Then time traveled at 60 mph = 3 - T
We then get the following DISTANCE equation: 61T + 60(3 - T) = 181
61T + 180 - 60T = 181
61T = 60T = 181 - 180
T, or time he traveled at 61 mph = {{{highlight_green(matrix(1,2, 1, hour))}}}
Time he traveled at 60 mph: 3 - 1, or {{{highlight_green(matrix(1,2, 2, hours))}}}