Question 1027790
Use x,y nomenclature.
{{{y=(x+4)/(3x-2)}}}
Interchange x,y and solve for y. The new y is the inverse.
{{{x=(y+4)/(3y-2)}}}
{{{x(3y-2)=y+4}}}
{{{3xy-2x=y+4}}}
{{{3xy-y=2x+4}}}
{{{y(3x-1)=2x+4}
{{{y=(2x+4)/(3x-1)}}}
{{{highlight(f^(-1)(x)=(2x+4)/(3x-1))}}}