Question 1028051
Use Cramer's rule,
{{{A=(matrix(3,3,
1,1,1,
2,4,1,
1,2,3))}}}
{{{abs(A)=6}}}
.
.
.
{{{A[x]=(matrix(3,3,
1,1,1,
1,4,1,
3,2,3))}}}
{{{abs(A[x])=0}}}
.
.
.
{{{A[y]=(matrix(3,3,
1,1,1,
2,1,1,
1,3,3))}}}
{{{abs(A[y])=0}}}
.
.
.
{{{A[z]=(matrix(3,3,
1,1,1,
2,4,1,
1,2,3))}}}
{{{abs(A[z])=6}}}
.
.
.
So,
{{{x=abs(A[x])/abs(A)=0/6=0}}}
{{{y=abs(A[y])/abs(A)=0/6=0}}}
{{{z=abs(A[z])/abs(A)=6/6=1}}}