Question 88466
let x be the larger number and y be the smaller number.

one number is 12 more than another 

x = y + 12

The sum of the smaller number and twice the larger number is 39.

y + 2x = 39


Substitute x in this equation

y + 2 (y +12) = 39

y + 2y + 24 = 39

3y + 24 =39

Subtract 24 on both sides, you will get

3y = 39 -24

3y =15
Divide by 3, you will get

y = 5

x = y + 12 = 5 + 12 = 17

Smaller Number = 5
Larger Number = 17