Question 1028024
Call the costs of roses and shrubs, r and s.  Then we write
11r + 8s = 90  and
4r + 7s = 45
Solve this system by multiplying the top by 4 and the bottom by 11 and subtracting them...we get
44r + 32s = 360
-(44r + 77s = 495)
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-45s = -135
s = $3 for shrubs
Now substitute back in and get
11r + 8(3) = 90
11r + 24 = 90
11r = 66
r = $6 for roses
so that one of each costs a total of
$9