Question 88302
{{{y=x^2-2x-3}}}

{{{y=x^2-2x+ 1 -1-3}}}

{{{y=(x^2-2x+ 1) -4}}}

{{{y=(x-1)^2-4}}}

vertex = (1, -4)

Put y = 0 in equation to find the x -intercept
{{{y=x^2-2x-3}}}


{{{x^2-2x-3 = 0}}}

(x - 3)(x+1) = 0

x = 3 & x = -1


Put x = 0 in equation to find the y -intercept

{{{y=x^2-2x-3}}}
y = -3