Question 1027968
Volume of metal available for cone = {{{(4/3)*pi*(r1^3-r2^3)}}}

where r1= 4 and r2=2 cm (radii)

4^3-2^3= 56

V = (4/3) *pi *56 

V cone = 1/3 pi r^2 h


=(1/3) *pi *4^2*h

Equate the volumes to get h

(4/3) *pi *56 =(1/3) *pi *4^2*h

56=4h

h=14 cm