Question 1027809
i'm not exactly sure what they are looking for.


the equation looks like it is already in factored form.


it appears to be 10 * (x+6) * (x + 0).


the form they are looking for is a * (x-r) * (x-s)


if i'm guessing correctly, then you would get:


a = 10
r = -6
s = 0


the unfactored equation would be 10x^2 + 60x = 0


you would factor out the gcf to get 10 * (x^2 + 6x)


if you tried to factor the quadrtic of x^2 + 6x using the quadratic formula, you would get:


a = 1
b = 6
c = 0


sqrt(b^2 - 4ac) = sqrt(36-4*1*0) = sqrt(36) = 6


quadratic formula of x = (-b +/- sqrt(b^2-4ac))/(2a) would become:


x = (-6 + 6) / 2 or x = (-6 -6) / 2


this would result in x = 0 or x = -6


one of the factors would be x.


the other factor would be x + 6


that agrees with what is shown.


i can't think of any other way to force the result to be in the form indicated.


i'll stick with my guess.


a = 10
r = -6
s = 0