Question 1027799
{{{7^(a+2)=9^(2a)}}}


{{{log7^(a+2)=log9^(2a)}}}


{{{(a+2)log7=(2a)log9}}}


{{{(a+2)/(2a)=log9/log7}}}


{{{(a+2)/(2a)=.95424/.84510}}}


{{{(a+2)/(2a)=1.12915}}}


{{{(a+2)=(2a)(1.12915)}}}


{{{(a+2)=(2.2583a)}}}


{{{(2)=(1.2583a)}}}


{{{a=1.58945}}}


Plug that number in for 'a' in original equation.