Question 1027792
Hi there,
Basically you have a rectangular 
based pyramid.
Volume = 1/3 base area x height.
Base area = 50 x 400 = 20000ft^2
Height is found by:
Finding diagonal of base.
Diagonal^2 = length^2 + Base^2
Diagonal^2 = 400^2 + 50^2
Diagonal = √162500
Diagonal = 403.11ft
Halve 403.11ft = 201.56ft
Consider you have a right angled
triangle.
Base = 201.56
To find the height:
Angle between base and hypotenuse
= 45 degrees.
Using Tan(theta) = Opposite/Adjacent
tan(45) = Opposite/201.56
Opposite (Height) = tan(45) x 201.56
Height = 326.48ft.
Volume = 1/3 base area x height.
(Base area = 50 x 400 = 20000ft^2)
(Height = 326.48ft.)
Volume = 1/3 x 20000 x 326.48
Volume = 2176533.33ft^3
Weight = 94 x 2176533.33
= 204594133 lbs
= 102297.07 tons
Hope this helps :-)