Question 88446
2x^2+3bx+b^2=0
using the quadratic equation we get:
x=(-3b+-sqrt[(3b)^2-4*2*b^2])/2*2
x=-3b+-sqrt[9b^2-8b^2])/4
x=(-3b+-sqrtb^2)/4
x=(-3b+-b)/4
x=(-3b+b)/4
x=-2b/4
x=-b/2 answer
x=(-3b-b)/4
x=-4b/4
x=-b answer.