Question 1027760
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Let *[tex \Large x] be the number of pounds of the $4.50 per pound component.  Then *[tex \Large 80\ -\ x] must be the number of pounds of the $2.50 per pound component.  *[tex \Large 4.5x] is the cost of the first component and *[tex \Large 2.5(80\ -\ x)] is the cost of the second component.  *[tex \Large 3.0(80)\ =\ 240] is the total cost of the mixture.  So:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 4.5x\ -\ 2.5(80\ -\ x)\ =\ 240]


Solve for *[tex \Large x] and then calculate *[tex \Large 80\ -\ x]


This works regardless of whether the grocer's name is Albert, or for that matter whether he or she is actually a grocer.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it

*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \  

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