Question 88446
Solve for x: 
2x^2 + 3bx + b^2 = 0 
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Use the quadratic formula to get:
x = [-3b+-sqrt(9b^2-4*2*b^2)]/4

x = [-3b +-sqrt(b^2)]/4

x = [-3b+-b]/4

x = -b or x = -b/2
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Cheers,
Stan H.