Question 1027751
<font face="Times New Roman" size="+2">


The radius of what?  The original circle or the increased area circle?


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ A\ =\ \pi{r^2}]


Hence:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ r\ =\ \sqrt{\frac{A}{\pi}}]


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it

*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \  

</font>