Question 1027646

Find all complex-number solutions

2x^2-3x-5=0

I just need to see steps on how to break this down. I know the first part is adding 5 to make C. 
<pre>Why would you want to add 5. Are you supposed to solve this by completing the square? If not, the trinomial can be factored as:
(2x - 5)(x + 1) = 0
2x - 5 = 0        OR         x + 1 = 0
{{{highlight_green(matrix(1,7, x, "=", 5/2, OR, x, "=", - 1))}}}. You are done!!
As seen there are NO COMPLEX-NUMBER solutions.