Question 1027601
Let x be the amount invested at 8%.  Thus 12000-x would be the amount invested at 6%.  The setup looks like this:
.08x + .06(12000-x) = 872
Now solve for x.
.08x + 720 - .06x = 872
.02x + 720 = 872
.02x = 152
x = $7600 invested at 8%
12000-x = $4400 invested at 6%