Question 1027605
(x-2)/(x+3)+ (10x)/(x^2-9) 
common denominator is (x+3)(x-3)
(x-2)(x-3)+10x is numerator, which is x^2-5x+6+10x=x^2+5x+6
that factors to (x+3)(x+2)
The denominator is (x+3)(x-3) after factoring
divide by (x+3)(x-3) and the (x+3) cancel
answer is
(x+2)/(x-3)