Question 1027567
{{{4=a*cosh(L/a)}}}
.
.
.
{{{2=a*cosh(0/a)}}}
{{{a=2}}}

.
.
.
So then,
{{{4=2*cosh(L/2)}}}
{{{cosh(L/2)=2}}}
{{{L/2=1.32}}}
{{{L=2.64}}}{{{m}}}
.
.
.
*[illustration cosh.JPG].