Question 88309
:
{{{7/((x^2-x-2))}}} + {{{1/((x+1))}}} = {{{3/((x-2))}}}
:
The 1st denominator can be factored:
{{{7/((x-2)(x+1))}}} + {{{1/((x+1))}}} = {{{3/((x-2))}}}
:
Multiplying thru (each term) by (x-2)(x+1) will rid us of the denominators:
:
7 + 1(x-2) = 3(x+1)
:
7 + x - 2 = 3x + 3; multiplied what's inside the brackets
:
5 - 3 = 3x - x
:
2 = 2x
:
x = 1
:
:
Substitute 1 for x in the original equation and confirm that equality reigns.