Question 88432
8x   .   x^2-4
____     _____  =
 
3x-6     2x+4

----------------
[8x/(3(x-2))] * [(x-2)(x+2)/2(x+2)]
Cancel the (x+2) factors to get

= [8x/(3(x-2))] * [(x-2)/2]

Cancel the (x-2) factors to get:
= [8x/(3)] * [1/2]

Cancel the "2" factors to get:


= 4x/3

Cheers,
Stan H.