Question 1025269
Call what he invests at 6%, x.  Thus he invests 10000-x at 7%.
The interest he gets from each is .06x and .07(10000-x).
So we set this up like this
.07(10000-x) = 7(.06x) - 35
Now solve for x...
700 - .07x = .42x - 35
735 = .49x
x = $1500 at 6%  and thus
10000-x = $8500 at 7%