Question 88411
Determine the measure of angle B of triangle ACB, given the following information: A=69degrees, a=25feet, b=16feet
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Using the Law of Sines you get:
SinB/b = SinA/a
SinB = 16[sin(69)/25]
SinB = 16*0.0373432...
SinB = 0.59749..
B = arc sin (0.59749...)
B = 36.69 degrees
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Cheers,
Stan H.