Question 1027188

2sinx+sin2x=0
-----

2sin(x) + 2sin(x)*cos(x)=0
sin(x) + sin(x)*cos(x)=0
sin(x)*(cos(x) + 1) = 0
sin(x) = 0
x = 0 + n*pi
--------------
cos(x) + 1 = 0
x = pi + n*2pi
-----
n = any integer in both solutions