<PRE><B>Question 88245</B>
   [(3x^2 + 14x + 15)/(3x^2 + 8x + 5)]/[(x^2 - x - 12)/(-3x^2 + 9x + 12)]
   Factorise  each expressions given and then simplify
   3x^2+14x+15 = 3x^2+9x+5x+15 = 3x(x+3)+5(x+3) = (x+3).(3x+5)
   3x^2+8x+5   = 3x^2+3x+5x+5  = 3x(x+1)+5(x+1) = (x+1).(3x+5)
    x^2-x-12   = x^2-4x+3x-12  = x(x-4)+3(x-4)  = (x-4).(x+3)
   -3x^2+9x+12 = -3x^2+12x-3x+12 = -3x(x-4)-3(x-4) = (x-4).(-3x-3)
    substituting  the values we get
    (x+3).(3x+5)/(x+1).(3x+5) = (x+3)/(x+1)
     (x-4).(x+3)/(x-4).(-3x-3) = (x+3)/(x-4)
       (x+3)/(x+1)divided by  (x+3)/(x-4)
      =(x+3).(x-4)/(x+3).(x+1)
      = (x-4)/(x+1) </PRE>