Question 1027037
{{{lny^3 = lnx^(1/3) - ln(x^2-1)+lnx^(4/3) + lnc}}}

{{{lny^3 = lnx^(5/3) - ln(x^2-1)+ lnc}}}

{{{lny^3 = ln((cx^(5/3))/(x^2-1))}}}

==> {{{y^3 = (cx^(5/3))/(x^2-1)}}}