<PRE><B>Question 1027194</B>
a car traveled 4032 mi at a certain speed. if the speed had been 16 mph faster, the trip could have been made in 6 hr less time. find the speed

let x=original speed
x+16=faster speed
travel time=distance /speed
4032/x-4032/(x+16)=6
lcd:x(x+16)
4032(x+16)-4032x=6x^2+96x
64512=6x^2+96x-64512
x^2+16x-10752
(x-96)(x+112)
x=96
x+16=112
original speed=96 mph
faster speed=112 mph</PRE>