Question 1027065
Let {{{p=x^2}}}.


{{{p^2-2p-4=0}}}
{{{p=(2+- sqrt(4-4*(-4)))/2}}}
{{{p=(2+- sqrt(20))/2}}}
{{{p=(2+- 2*sqrt(5))/2}}}
{{{p=1+- sqrt(5)}}}


{{{x^2=1+- sqrt(5)}}}


{{{highlight(x=0+- (1+- sqrt(5)))}}}



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You should examine that number or expression further.

There are two "plus or minus"es.  They are these:
{{{system(-1-sqrt(5),-1+sqrt(5),1-sqrt(5),1+sqrt(5))}}} which are four separate numbers.  Each has multiplicity of 1.