Question 1027071
You want  {{{(something*y+constOne)(somethingelse*y+constTwo)}}}.


You know how to factorize 4 and how to factorize 7.

Which of these will work?
<pre>
(2x  1)(2x  7)
(2x  7)(2x  1)
(x  1)(4x  7)
(x  7)(4x  1)
</pre>