Question 1027140
<pre>x  short leg
3x  long leg
x^2  hypotenuse</pre>


Pythagorean Formula gives this:    {{{x^2+(3x)^2=x^2}}}



{{{x^2+9x^2=x^2}}}


{{{9x^2=0}}}


{{{x^2=0}}}


{{{x=0}}}

The description does not work.


You should expect from the long and short legs is  {{{x^2+9x^2}}} is the square of the hypotenuse, which is  {{{10x^2}}}.  You will then have  hypotenuse is  {{{x*sqrt(10)}}}.
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The perimeter should be  {{{3x+x+x*sqrt(10)=4x+x*sqrt(10)}}}.