Question 88317
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 1)  d = c-s/n   or  s/n = c-d   therefore s = n(c-d)  is the solution

 2)  a = 1/2.h(B+b)   or 2a = h.(B+b)  therefore h = 2a/(B+b) is the solution.

  3)Height of the trapezoid  h = 16 m  one of the base  = a = 20 m
    area of the trapezoid A = 224 sqm  to find the value of the other base = b
     A = 1h(a+b)/2     2A =  h(a+b) or 2A/h = (a+b)    therefore (a+b) = 2.224/16       or a+b = 2.14 = 28  therefore a+b = 28   or b = 28-20 = 8 m
         the value of the other base = b = 8m

   4)  Let the two consecutive numbers  be x and (x+1)  sum of the numbers = 145
    therefore x+(x+1) = 145  i.e, 2x+1 = 145  ,  2x = 145-1 = 144  or x=144/2
     therefore x = 72  and x+1 = 72+1 = 73  the no's are 72 and73

  5)  length of the board  = 98 inch  let the length of the two pieces of boards 
     be x and (x+10)   
     therefore x+x+10 = 98  or 2x = 98-10  or 2x = 88  x = 88/2 = 44
      the length of one board = x = 44 inch
      the length of the other board  = x+10 =44+10 =54 inch