Question 88297
Solve for y in the equation of the given line: 
2x - 3y = 6
-3y = -2x +6


{{{(-3y)/-3=(-2x)/(-3) +6/-3}}}
{{{y=(2/3)x -2}}}

The slope of this line is {{{2/3}}}, so the slope of a line that is perpendicular to this line is the negative reciprocal, which is {{{-3/2}}}.  
Given that the y intercept is 2 means that b=2.  


y=mx+b
{{{y=(-3/2)x+2}}}


R^2