Question 1027062
{{{f(x)=x^2-3x+5}}}
{{{f(x)=(x^2-3x+9/4)+5-9/4}}}
{{{f(x)=(x-3/2)^2+20/4-9/4}}}
{{{f(x)=(x-3/2)^2+11/4}}}
Vertex : ({{{3/2}}},{{{11/4}}})
Axis of symmetry : {{{x=3/2}}}
X-intercepts:
{{{(x-3/2)^2=-11/4}}}
There are no real roots.
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*[illustration dx4.JPG].