Question 1026941
At least 2 means "2, 3, 4, and 5".
So find the probability of each and add the probabilities up. 
You could also find the probability of 0 and 1, add them, and subtract by 1.
That may be the easiest way. 
You're correct, there are 32 possible outcomes. 
One of them is no heads.
TTTTT
So the probability of 0 heads is,
{{{P(0)=1/32}}}
For one head, there are five possible outcomes,
HTTTT THTTT TTHTT TTTHT TTTTH
So there are 5 possible outcomes and then,
{{{P(1)=5/32}}}
So then the added probability is,
{{{P=1/32+5/32=6/32=3/16}}}
We're looking for the complement so,
{{{P(H>=2)=1-3/16}}}
{{{P(H>=2)=13/16}}}