Question 1026998
ii:
What base?  Maybe better help if you say.


i:
{{{ln((2x-1)^4)-ln(9)=ln((x-1)^2)+ln((x+1)^2)}}}
{{{ln((2x-1)^4/9)=ln((x-1)^2*(x+1)^2)}}}
{{{(2x-1)^4/9=(x-1)^2*(x+1)^2}}}
{{{(2x-1)^4=9(x-1)^2(x+1)^2}}}
{{{(2x-1)^4=9(x^2-1)^2}}}-------continue to solve this fourth-degree equation.