Question 1026867
F(x)= 3x-2 over x^2+2x-24 - x-3 over x^2-9 
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F(x) = (3x-2)/[(x+6)(x-4)] - (x-3)/[(x+3)(x-3)]
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F(x) = (3x-2)/[(x+6)(x-4)] - 1/[(x+3)
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F(x) = [(x+3)(3x-2)-(x+6)(x-4)]/[(x+3)(x+6)(x-4)]
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F(x) = [3x^2 +7x -6 - x^2 - 2x +24]/[(x+3)(x^2-2x-24)]
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F(x) = [2x^2 +5x + 18]/[(x+3)(x^2-2x-24)]
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Cheers,
Stan H.
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